Integer To English Words
XXX.Number to Words
String
Simulation
Problem Statement:
Convert a non-negative integer into its English words representation. For example, given 123
, return "One Hundred Twenty Three"
. Assume the input does not exceed 231 - 1.
Algorithm:
- Handle the special case of zero by returning "Zero".
- Break the number into groups of three digits, starting from the least significant digits (thousands, millions, etc.).
- Use a helper function to convert each group of three digits to words:
- Numbers less than 20 are directly mapped to their English words.
- Numbers less than 100 are split into tens and units.
- Numbers less than 1000 are processed by splitting into hundreds, tens, and units.
- Combine the English words for each group with their corresponding place value (e.g., "Thousand", "Million").
- Trim any extra spaces and return the result.
Complexity:
Time: O(n), where n
is the number of digits in the number. Each digit is processed a constant number of times. | Space: O(1), as no additional data structures are used apart from a few fixed arrays.
Java Implementation:
class Solution {
private final String[] LESS_THAN_20 = {"", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen"};
private final String[] TENS = {"", "Ten", "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety"};
private final String[] THOUSANDS = {"", "Thousand", "Million", "Billion"};
public String numberToWords(int num) {
if (num == 0) return "Zero"; // Special case for zero
int i = 0; // Tracks the place value (thousands, millions, etc.)
String words = ""; // Resultant English words representation
// Process each group of three digits
while (num > 0) {
if (num % 1000 != 0) // Only process non-zero groups
words = helper(num % 1000) + THOUSANDS[i] + " " + words;
num /= 1000; // Move to the next higher place value
i++;
}
return words.trim(); // Remove any trailing spaces
}
private String helper(int num) {
if (num == 0) return ""; // Base case for recursion
if (num < 20) // Numbers less than 20 are directly mapped
return LESS_THAN_20[num] + " ";
if (num < 100) // Split tens and units
return TENS[num / 10] + " " + helper(num % 10);
// Split hundreds, tens, and units
return LESS_THAN_20[num / 100] + " Hundred " + helper(num % 100);
}
}
Python Implementation:
class Solution:
def __init__(self):
self.less_than_20 = ["", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten",
"Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen"]
self.tens = ["", "Ten", "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety"]
self.thousands = ["", "Thousand", "Million", "Billion"]
def numberToWords(self, num: int) -> str:
if num == 0:
return "Zero"
i = 0
words = ""
while num > 0:
if num % 1000 != 0:
words = self.helper(num % 1000) + self.thousands[i] + " " + words
num //= 1000
i += 1
return words.strip()
def helper(self, num: int) -> str:
if num == 0:
return ""
if num < 20:
return self.less_than_20[num] + " "
if num < 100:
return self.tens[num // 10] + " " + self.helper(num % 10)
return self.less_than_20[num // 100] + " Hundred " + self.helper(num % 100)
C++ Implementation:
class Solution {
vector less_than_20 = {"", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine",
"Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen",
"Seventeen", "Eighteen", "Nineteen"};
vector tens = {"", "Ten", "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety"};
vector thousands = {"", "Thousand", "Million", "Billion"};
public:
string numberToWords(int num) {
if (num == 0) return "Zero";
int i = 0;
string words = "";
while (num > 0) {
if (num % 1000 != 0)
words = helper(num % 1000) + thousands[i] + " " + words;
num /= 1000;
i++;
}
return trim(words);
}
string helper(int num) {
if (num == 0) return "";
if (num < 20) return less_than_20[num] + " ";
if (num < 100) return tens[num / 10] + " " + helper(num % 10);
return less_than_20[num / 100] + " Hundred " + helper(num % 100);
}
string trim(const string& str) {
auto start = str.find_first_not_of(' ');
auto end = str.find_last_not_of(' ');
return str.substr(start, end - start + 1);
}
};